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In triangle ABC, given angle ACB = θ

The side opposite to the angle ‘θ’ is the opposite side.

This implies, side AB = Opposite side = 6m

The side adjacent to angle ‘θ’ is the adjacent side.

This implies, side BC = Adjacent side = 8m

Tangent of θ written as tan(θ) = (Opposite side)/ (Adjacent side)

Therefore tan(θ) = 6/8

Given: sin(θ) = 3/5 and cos(θ) = 4/5

Tangent of the angle θ is also written as ‘tan(θ)’.

tan(θ) is the ratio of sin(θ) and cos(θ).

This gives: tan(θ) = sin(θ)/ cos(θ)

This implies, tan(θ) = (3/5)/ (4/5) -> Now taking the reciprocal we get: (3/5) * (5/4)

This gives: tan(θ) = 3/4.

Therefore we get, tan(θ) = 3/4.