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Given: AB is parallel to CD.

EF is the transversal.

Value of a= 115°

If a transversal crosses a pair of parallel lines, then the alternate exterior angles are equal to each other.

Here, ‘a’ and ‘b’ are alternate exterior angles and hence a= b= 115°.

Given, a transversal crosses a pair of parallel lines.

Angle x = 96°, let its adjacent angle be = y

On a straight line, sum of two angles which are adjacent to each other = 180° (supplementary)

So x + y = 180°

96° + y = 180°

This implies: y = 180° - 96° = 84°

Therefore, its adjacent angle is 84°