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The domain of the function is all the possible input values of X.

First step: Equate the dominator [(x - 2) (x- 3)] = 0

This gives the values x = 2 and x = 3;

Hence when x = 2, 3 the function is undefined as denominator = 0;

Therefore the domain of the function is: R - {2 ,3}

Given is a function f(x) = 10x/ [(x + 6) (x- 12)];

The domain of the function is all the possible input values of X.

First step: Equate the dominator [(x + 6) (x- 12)] = 0

This gives the values x = -6 and x = 12;

Hence when x = -6, 12 the function is undefined as denominator = 0;

Therefore the domain of the function is: R - {-6 ,12}