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From the condition of a particular given problem a student may construct a simple equation of one unknown or he is at liberty to construct the simultaneous equations of two or more unknowns for the same problem.

So construction of an algebraic equation from a word problem is very much important to solve the problem.

So the number = 10 x + y

When 29 is subtracted from the number, it becomes

= (10 x + y) – 29

= (10 x + y) – (30 – 1)

= (10 x – 30) + y + 1

= 10 (x – 3) + (y + 1)

Therefore by the problem,

x– 3 = y + 1 … (1)

Or, x – y = 4 … (2)

And x + y = 14

Adding (1) and (2)

(x+y)+(x-y) =14+4

x=9

Similarly subtracting (1) from (2) then we will get y = 5

Therefore the number=10x+y=10(9) +5=95

Other example could be: -A does a work for 16 days and B does for 15 days. The wage of 4 days for A is less than the wages of 7 days for B by Rs. 4. If Rs. 500 is paid to them, find their daily wages.